2x^2+2y^2-4x+8y=32

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Solution for 2x^2+2y^2-4x+8y=32 equation:


Simplifying
2x2 + 2y2 + -4x + 8y = 32

Reorder the terms:
-4x + 2x2 + 8y + 2y2 = 32

Solving
-4x + 2x2 + 8y + 2y2 = 32

Solving for variable 'x'.

Reorder the terms:
-32 + -4x + 2x2 + 8y + 2y2 = 32 + -32

Combine like terms: 32 + -32 = 0
-32 + -4x + 2x2 + 8y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-16 + -2x + x2 + 4y + y2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-16 + -2x + x2 + 4y + y2)' equal to zero and attempt to solve: Simplifying -16 + -2x + x2 + 4y + y2 = 0 Solving -16 + -2x + x2 + 4y + y2 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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